Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is give. E= 20.3 cm, sample standard deviation =321.0 cm.
1201 |
961 |
916 |
Cannot tell from the given information |
Solution :
Given that,
standard deviation = = 321.0 cm
margin of error = E = 20.3
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Sample size = n = ((Z/2 * ) / E)2
= ((1.960 * 321.0) / 20.3)2
= 961
Sample size = 961
Answer 961 is correct.
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