A sample of 30 observations is selected from a normal population. The sample mean is 22, and the population standard deviation is 4. Conduct the following test of hypothesis using the 0.01 significance level. H0: μ ≤ 20 H1: μ > 20
What is the value of the test statistic? (Round your answer to 2 decimal places.)
What is the p-value? (Round your answer to 4 decimal places.)
Interpret the p-value? (Round your final answer to 2 decimal places.) (% chance of finding a z-value this large by "sampling error" when H0 is true)
Solution :
= 20
= 22
= 4
n = 30
This is the right tailed test .
The null and alternative hypothesis is
H0 : 20
Ha : > 20
Test statistic = z
= ( - ) / / n
= ( 22- 20) /4 / 30
= 2.74
p(Z > 2.74) = 1-P (Z < 2.74) =0.0031
P-value = 0.0031
= 0.01
0.0031< 0.01
Reject the null hypothesis .
There is sufficient evidence to suggest that
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