Question

In a completely randomized design, 12 experimental units were used for the first treatment, 15 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance (to 2 decimals, if necessary). If the answer is zero enter "0".

Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F |
p-value |

Treatments | 1400 | ||||

Error | |||||

Total | 1800 |

At a .05 level of significance, is there a significant difference between the treatments?

The p-value is - Select your answer -less than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 9

What is your conclusion?

Answer #1

df treatments = k -1 = 3 - 1 =2

df error = N-k = (12+15+20) - 3 = 44

df total = N-1 = 47-1= 46

means square = SS/df

Fstat = MS treatment/MSerror = 700/90.09=77

p-value = 0.0000

Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square |
F |
p-value |

Treatments | 1400.0 | 2 | 700.0000 | 77.0000 | 0.0000 |

Error | 400.0 | 44 | 9.0909 | ||

Total | 1800.0 | 46 |

p-value is less than 0.01

reject Ho,

there is a significant difference between the treatments at α=0.05

In a completely randomized design, 12 experimental units were
used for the first treatment, 15 for the second treatment, and 20
for the third treatment. Complete the following analysis of
variance (to 2 decimals, if necessary). If the answer is zero enter
"0".
Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
p-value
Treatments
1,200
Error
Total
1,800
At a .05 level of significance, is there a significant
difference between the treatments?
The -value is - Select...

In a completely randomized design, 12 experimental units were
used for the first treatment, 15 for the second treatment, and 20
for the third treatment. Complete the following analysis of
variance (to 2 decimals, if necessary). If the answer is zero enter
"0".
Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
p-value
Treatments
1100
Error
700
44
xx
xxxx
Total
1800
xx
xxx

The following data are from a completely randomized design.
Treatment
Treatment
Treatment
A
B
C
32
46
33
30
45
36
30
46
35
26
48
36
32
50
40
Sample mean
30
47
36
Sample variance
6
4
6.5
At the = .05 level of significance, can we reject
the null hypothesis that the means of the three treatments are
equal?
Compute the values below (to 1 decimal, if necessary).
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In an experiment designed to test the output levels of three
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Use A=.05.
Source
of Variation
Sum
of Squares
Degrees
of Freedom
Mean Square
(to 2 decimals)
(to 2 decimals)
-value
(to 4 decimals)
Treatments
150
Error
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420
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In a completely randomized design, eight experimental units were
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Source
of Variation
Sum
of Squares
Degrees
of Freedom
Mean
Square
F
p-value
Treatments
360
Error
Total
470

In a completely
randomized design, seven experimental units were used for each of
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decimal places. If your answer is zero enter "0".
Source of
Variation
Sum of
Squares
Degrees of
Freedom
Mean Square
F
p-value
Treatments
300
Error
Total
460
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In a completely randomized experimental design, 6 experimental
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Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
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2434220
3
811406.7
Error (Within Treatments)
3883910
20
194195.5
Total
6318130
23
1. What is the null and alternative
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3. What is the rejection rule for the F test at
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To study the effect of temperature on yield in a chemical
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Temperature
50°C
60°C
70°C
31
28
24
21
29
29
33
32
29
36
21
31
29
25
32
Construct an analysis of
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Source of
Variation
Sum of
Squares
Degrees of
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Mean Square
F
p-value
Treatments
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Total
Use a .05...

To study the effect of temperature on yield in a chemical
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Temperature
50°C
60°C
70°C
31
30
25
21
31
30
33
34
30
36
23
32
29
27
33
a. Construct an analysis of variance table (to
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Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
p-value
Treatments
Error
Total
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o study the effect of temperature on yield in a chemical
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Temperature
50°C
60°C
70°C
32
33
29
22
34
34
34
37
34
37
26
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30
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37
Construct an analysis of
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Source of
Variation
Sum of
Squares
Degrees of
Freedom
Mean Square
F
p-value
Treatments
Error
Total
Use a .05...

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