x |
P(Xx) |
0 |
|
1 |
|
… |
|
n |
Here p=0.05 is same for all, n=10 is constant, events are independent only two outcomes
Hence all properties of binomial are satisfied
a. Mean value is
b. Variance is
So Standard deviation is
c.
x | P(x)=BINOMDIST(x,n,p,0) |
0 | 0.5987 |
1 | 0.3151 |
2 | 0.0746 |
3 | 0.0105 |
4 | 0.0010 |
5 | 0.0001 |
6 | 0.0000 |
7 | 0.0000 |
8 | 0.0000 |
9 | 0.0000 |
10 | 0.0000 |
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