x 
P(Xx) 
0 

1 

… 

n 
Here p=0.05 is same for all, n=10 is constant, events are independent only two outcomes
Hence all properties of binomial are satisfied
a. Mean value is
b. Variance is
So Standard deviation is
c.
x  P(x)=BINOMDIST(x,n,p,0) 
0  0.5987 
1  0.3151 
2  0.0746 
3  0.0105 
4  0.0010 
5  0.0001 
6  0.0000 
7  0.0000 
8  0.0000 
9  0.0000 
10  0.0000 
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