Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) μ = 102; σ = 17 P(x ≥ 120) =
Solution :
Given that ,
mean = = 102
standard deviation = = 17
P(x 120 ) = 1 - P(x 120 )
= 1 - P((x - ) / (102 - 120) /17 )
= 1 - P(z -1.06 )
= 1 - 0.1446
= 0.8554
Probability = 0.8554
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