Question

In an experiment designed to test the output levels of three different treatments, the following results were obtained: SST= 420 SSTR=150 NT=19. Set up the ANOVA table and test for any significant difference between the mean output levels of the three treatments. Use A=.05.

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square (to 2 decimals)	(to 2 decimals)	-value (to 4 decimals)
Treatments	150
Error
Total	420

The P-value is - Select your answer -less than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 9 .

What is your conclusion?

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Answer 1

Given

No of treatment = k = 3

No of observation =n=20

Df due to treatment = k-1 = 3-1=2

Df due to error =n-k =20-3= 17

SS total = SS treatment + SS error

SS error = 420-150

SS error = 270

MS treatment = SS treatment / df treatment

= 150/2

MS treatment = 75. 00

MS error = SS error / df error

= 270/17

MS error = 15.88

F = ms treatment / MS error

= 75.00/15.88

F = 4.72

The p value for f ratio is 0.0234.

P value = 0.0234

P value is less than 0.05.

So p value is between 0.01 and 0.025.