Question

Listed below are systolic blood pressure measurements​ (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. What can be​ concluded?

Right arm	147	149	142	135	136
Left arm	178	170	192	156	147

In this​ example,

mu Subscript dμd

is the mean value of the differences d for the population of all pairs of​ data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis​ test?

A.

H0​: μd=0

H1​: μd≠0

B.

H0​: μd=0

H1​: μd<0

C.

H0​: μd≠0

H1​: μd=0

D.

H0​: μd≠0

H1​: μd>0

Identify the test statistic.

t= ​(Round to two decimal places as​ needed.)

Identify the​ P-value.

​P= ​(Round to three decimal places as​ needed.)

Since the​ P-value is (less/greater) than the significance​ level, (reject/fail to reject) the null hypothesis. There (is/is not) sufficient evidence to support the claim of a difference in measurements between the two arms.

Answer 1

1()option A:

H0​: μd=0

H1​: μd≠0

2)

test statistic t =-4.06
3)

p value = 0.015

Since the​ P-value is less .....reject .........there is sufficient,,,,,,,,,