Question

Satisfied? A 2010 poll asked people of a certain region whether they were satisfied with their financial situation. A total of 342 out of 831 people said they were satisfied. The same question was asked in 2012, and 304 out of 1162 people said they were satisfied. Part: 0 / 20 of 2 Parts Complete Part 1 of 2 (a) Construct a 90% confidence interval for the difference between the proportions of adults who said they were satisfied in 2012 and 2010. Let p1 denote the proportion of adults who said they were satisfied in 2010 and let p2 denote the proportion of adults who said they were satisfied in 2012. Use the TI-84 Plus calculator and round the answers to three decimal places.

A 90% confidence interval for the difference between the proportions of adults who said they were satisfied in 2012 and 2010 is < p1 - p2 <

Answer #1

The statistical software output for this problem is :

A 90% confidence interval for the difference between the proportions of adults who said

they were satisfied in 2012 and 2010 is

**0.115** < p1 - p2 <
**0.185**

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[________, ________]

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[,]

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