Data collected on the discharge of the Colorado River and speed are given in the table:
Discharge (ft3) | Speed |
---|---|
1.3 | 2.3 |
2.2 | 0.99 |
5.8 | 3.5 |
11 | 5 |
12 | 16 |
14 | 22 |
16 | 27 |
21 | 14 |
49 | 33 |
Find r2, and interpret the results.
0.67; The least-squares regression line, given by ŷ = 3.95 + 0.82x, is a good fit for the data. 0.82; The least-squares regression line, given by ŷ = 3.95 + 0.82x, is not a good fit to the data. 0.82; The least-squares regression line, given by ŷ = 0.82 + 3.95x, is a good fit for the data. 0.67; The least-squares regression line, given by ŷ = 3.95 + 0.67x, is not a good fit for the data.
In Excel type all data, here speed (y) depends on the discharge of corolado river (x variable)
To run regression
Data-data analysis- regression - choose x and y array - ok
Then from the out put we get,
y^ = 3.9469 + 0.667 * x
y^ = 3.95 + 0.67 * x. ( On rounding)
And R^2 = 0.67
That means only 67% of variation in y is explained by the independent variable in the model
So this The least-squares regression line, given by ŷ = 3.95 + 0.67x, is not a good fit for the data.
Option 4
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