If n=10, ¯xx(x-bar)=34, and s=4, find the margin of error at a
95% confidence level
Give your answer to two decimal places.
Solution :
Given that,
= 34
s =4
n = Degrees of freedom = df = n - 1 =10 - 1 = 9
a ) At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2= 0.05 / 2 = 0.025
t /2,df = t0.025,9 = 2.262 ( using student t table)
Margin of error = E = t/2,df * (s /n)
= 2.262 * (4 / 10)
= 2.86
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