Giving a test to a group of students, the grades and gender are
summarized below
A | B | C | Total | |
Male | 17 | 10 | 5 | 32 |
Female | 3 | 8 | 13 | 24 |
Total | 20 | 18 | 18 | 56 |
Let ππ represent the percentage of all male students who would
receive a grade of C on this test. Use a 95% confidence interval to
estimate p to three decimal places.
Enter your answer as a tri-linear inequality using decimals (not
percents).
< p <
Given that,
Point estimate = sample proportion = = x / n = 5 / 18 = 0.27 8
Z/2 = 1.96
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.96 * (((0.2778 * 0.7222) / 18)
= 0.207
A 95% confidence interval for population proportion p is ,
- E < p < + E
0.278 - 0.207 < p < 0.278 + 0.207
0.071 < p < 0.485
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