1. A biopsychologist is interested in studying the effects of marijuana on cognitive skills by studying a group of 7 rats. He puts each rat in a maze and measures the time it takes the rat (in minutes) to find the cheese at the end of the maze. He then puts a mask on the rat and has it inhale marijuana smoke for 5 seconds. He then puts the rat back in the maze, and records its time to reach the cheese. Twenty minutes later he puts the rat back in the maze to test for lasting effects of the drug. The tables below summarize the data and part of the data analysis:
Source SS df MS F p eta2
IV 33.24 2 ___ ____ ___ ____
Error 43.43 12 ___
Subjects 27.13 6
Total ____ 20
a. Describe the statistical test to be done.
b. State the null and alternative hypotheses.
c. What is the critical value of the test statistic? What is the decision rule for rejecting the null hypothesis?
CV: _________________________ df:___________ Reject H0 if F ________________
Based on the findings presented in your summary table, did you reject Ho? (Circle or highlight response)
Reject Ho Fail to reject Ho
Source | SS | df | MS | F | p | eta2 |
IV | 33.24 | 2 | 16.62 | 4.592 | .033077 | 32.02% |
Error | 43.43 | 12 | 3.619 | |||
Subjects | 27.13 | 6 | ||||
Total | 103.8 | 20 |
a)The statistical test to be done is ANOVA. Above is the table in which i have specified all the missing values.
b) The null and alternative hypothesis is as follows:
Ho:The time required for rats to reach at cheese is same before and after marijuana that is marijuana has no significant impact on rats
H1:The time required for rats to reach at cheese is different before and after marijuana that is marijuana has significant impact on rats.
c)
CV=4.592
df=(2,12)
table value of F is =3.885
Reject Ho if F>3.885 (at 5%)
d)
Reject Ho.
As the critical value is greater than observed value reject Ho.
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