Salaries of 34 college graduates who took a statistics course have a mean of $68,700. Assuming a standard deviation of $13,685. Construct a 95% confidence interval for estimating the population mean.
Solution :
Given that,
Point estimate = sample mean =
= 68700
Population standard deviation =
= 13685
Sample size = n = 34
At 95% confidence level
= 1 - 95%
= 1 - 0.95 =0.05
/2
= 0.025
Z/2
= Z0.025 = 1.96
Margin of error = E = Z/2
* (
/n)
= 1.96 * (13685 /
34)
= 2346.96
At 95% confidence interval estimate of the population mean is,
± E
68700 ± 2346.96
(66353.04 , 71046.96)
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