Question

The probability that a pale of fruits contain rotten fruit is 8.23%. The probability that it...

The probability that a pale of fruits contain rotten fruit is 8.23%. The probability that it contains unripe fruit is 5.08%. The probability that it contains both is 3.21%. What is the probability that a randomly selected fruit from the pale is rotten or unripe?

Math   Statistics-And-Probability   
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Answer #1

Probability that a pale of fruits contains rotten fruit is P(A) = 8.23 % or 0.0823

Probability that a pale of fruits contains unripe fruit is P(B) = 5.08% or 0.0508

Probability that a pale of fruits contains both rotten fruit and unripe is P(A∩B) = 3.21% or 0.0321

probability that a randomly selected fruit from the pale is rotten or unripe P(AUB) = ?

Using the formula

P(AUB) = P(A) + P((B) - P(A∩B)

= 0.0823 + 0.0508 - 0.0321

   = 0.101 or 10.01 % Answer

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