Question

	# of Patients
	Year
Month	2015	2016
1	4825	5262
2	4752	5435
3	4948	5481
4	5041	6081
5	5300	5936
6	5232	5627
7	5151	5856
8	5585	5763
9	5520	5924
10	5136	5787
11	5077	5474
12	5300	5699

d. You set your level of significance at alpha = 0.05 and determine your t-critical value of 2.074 since you are decided to conduct a t-test.
What is your decision rule (state when would you reject the null hypothesis and when you would fail to reject the null hypothesis)
e. Using Data Analysis in Excel, you obtain the following table. Make a conclusion. Your conclusion should have two parts.
	1) Do you reject or fail to reject the null hypothesis based on your decision rule?
	2) Answer the question (Is there a difference in the average number of patients being seen in the emergency room between 2015 and 2016?) based on your decision.
	t-Test: Two-Sample Assuming Unequal Variances
		2016	2015
	Mean	5693.75	5155.583333
	Variance	59352.205	63610.44697
	Observations	12	12
	Hypothesized Mean Difference	0
	df	22
	t Stat	5.3164387
p-value-->	P(T<=t) two-tail	2.457E-05
	t Critical two-tail	2.0738731

Answer 1

To test whether there is a difference in the average number of patients being seen in the emergency room between 2015 and 2016,

i.e.to test against

Here,

The value of the test statistic

and P-value = 0

Since P-value < 0.05, so we reject H₀ at 5% level of significance and we can conclude that there is significant difference in the average number of patients being seen in the emergency room between 2015 and 2016.