A concerned parents group determined the number of commercials shown in each of 5 childrens programs over a period of time. Find the standard deviation for the distribution shown.
Number of commercials X 5 6
7 8
9
Probability P
(X)
0.2 0.25 0.38 0.10 0.07
A.1.123
B.1.273
C.1.541
D.1.341
Solution:
Given that,
X | P(X) | X*P(X) | X^2*P(X) |
5 | 0.2 | 1 | 5 |
6 | 0.25 | 1.5 | 9 |
7 | 0.38 | 2.66 | 18.62 |
8 | 0.1 | 0.8 | 6.4 |
9 | 0.07 | 0.63 | 5.67 |
Sum | 1 | 6.59 | 44.69 |
Mean :
= X * P(X)
= 6.59
Standard deviation:
= X2 * P(X) - ()2
= 44.69 - ( 6.59 )2
= 1.2619
= 1.123
Option A is correct.
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