Question

40. A cell phone manufacturer claims that its phone will last for more than 8 hours...

40. A cell phone manufacturer claims that its phone will last for more than 8 hours of continuous talk time when the battery is fully charged. To test this claim at a​ 10% level of​ significance, a random sample of 18 phones were selected. The results showed a sample mean of 8.2 hours and a sample standard deviation of 0.4 hour.

Based on the data and hypothesis​ test, can you dispute the cell phone​ manufacturer’s claim?

A.

YES

B.

NO

C.

there is not enough information to answer this question

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

vs

=2.12

Degree of freedom =n-1 = 18-1 = 17

P value is 0.0245 < 0.10

TDIST(2.12,17,1).....................for p value by using Excel command.

We reject H0.

We have sufficient evidence to say that,  its phone will last for more than 8 hours of continuous talk time when the battery is fully charged.

Option A) is correct.

Yes.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A cell phone manufacturer claims that the batteries in its latest model provide 20 hours of...
A cell phone manufacturer claims that the batteries in its latest model provide 20 hours of continuous use. In order to verify this claim, and independent testing firm checks the battery life of 100 phones. They find that the batteries in these 100 phones last an average of 19 hours with a standard deviation of 5 hours. Conduct an appropriate hypothesis test to check whether the results from this sample provide sufficient evidence that the true mean battery life is...
A company that produces cell phone batteries claims their new battery last more than 30 hours....
A company that produces cell phone batteries claims their new battery last more than 30 hours. To investigate this claim a consumer advocacy group collected the following random sample for number hours that each battery worked: 50, 40, 35, 25, 60, 45, 30, 50, 30, 10. Is there a sufficient evidence to accept the company’s claims using 0.01 significance level?
A cell phone manufacturer claims that, if properly charged, their phone batteries will operate for 48...
A cell phone manufacturer claims that, if properly charged, their phone batteries will operate for 48 hours. A study of 5000 batteries is undertaken and 15 stop operating in under 48 hours. Do these results support a claim that less than 0.2 percent of the company’s batteries will fail during the 48 hour period? Use a hypothesis test with ?=0.01. Be sure to explicitly state: The null and alternative hypotheses The test statistic equation and value Your conclusion
A phone manufacturer wants to compete in the touch screen phone market. He understands that the...
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life of just 6 hours. The manufacturer claims that while the new touch phone is more expensive, its battery life is more than twice as long as that of the leading product. In order to test the claim, a researcher samples 55 units of the new phone and finds that the sample battery life averages 12.2 hours with a...
A marketing manager for a cell phone company claims that the percentage of children aged 8-12...
A marketing manager for a cell phone company claims that the percentage of children aged 8-12 who have cell phones differs from 61%. In a survey of 826 children aged 8-12 by a national consumers group, 545 of them had cell phones. Can you conclude that the manager's claim is true? Use the α=0.10 level of significance and the P-value method with the TI-84 Plus calculator. a. state null and alternative hypothesis. what tail is the hypothesis test? b. Compute...
The manufacturer of a cell phone component is attempting to increase the component's lifespan by changing...
The manufacturer of a cell phone component is attempting to increase the component's lifespan by changing the formula of the material it uses to make that component. Historically, the component has an average (μ) lifespan of 5,000 hours. A sample test is run with 22 cell phones that contain the new component and the average life span for the sample (x̄) is 5,100 hours with a standard deviation (s) of 50 hours. Did the new material increase the component's lifespan?...
6. A manufacturer claims that a customer will nd no more than 8% defective knee braces...
6. A manufacturer claims that a customer will nd no more than 8% defective knee braces in a large shipment. A customer decides to test this claim after reading an article in the American Journal of Sports Medicine, which discusses the force exerted on a knee brace used for injured athletes and convinces the customer that high quality is essential. A random sample of 200 braces is selected from the shipment, and 28 defectives are found. Test the manufacturer's claim...
A manufacturer claims that the mean lifetime of its lithium batteries is less than 1520 hours....
A manufacturer claims that the mean lifetime of its lithium batteries is less than 1520 hours. A homeowner selects 27 of these batteries and finds the mean lifetime to be 1498 hours with a standard deviation of 76 hours. Test the manufacturer's claim. Use α = 0.10. A. P-value = 0.112 > 0.02; do not reject H0; There is not enough evidence support the claim, that mean is less than 1500. B. P-value = 0.072 > 0.05; do not reject...
A manufacturer claims that the mean lifetime of its lithium batteries is less than 1500 hours....
A manufacturer claims that the mean lifetime of its lithium batteries is less than 1500 hours. A homeowner selects 25 of these batteries and finds the mean lifetime to be 1480 hours with a standard deviation of 80 hours. Test the manufacturer's claim. Use α = 0.10. A. P-value = 0.112 > 0.10; do not reject H0; There is not enough evidence support the claim, that mean is less than 1500. B. P-value = 0.112 > 0.05; do not reject...
A manufacturer claims that the mean lifetime of its lithium batteries is less than 1120 hours....
A manufacturer claims that the mean lifetime of its lithium batteries is less than 1120 hours. A homeowner selects 25 of these batteries and finds the mean lifetime to be 1100 hours with a standard deviation of 75 hours. Test the manufacturer's claim. Use α = 0.01. A. P-value = 0.110 > 0.01; do not reject H0; There is not enough evidence support the claim, that mean is less than 1120. B. P-value = 0.097 > 0.01; do not reject...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT