a)
X ~ N ( µ = 32.4 , σ = 0.0548 )
We covert this to standard normal as
P ( X < x) = P ( (Z < X - µ ) / σ )
P ( X > 32.49 ) = P(Z > (32.49 - 32.4 ) / 0.0548 )
= P ( Z > 1.64 )
= 1 - P ( Z < 1.64 )
= 1 - 0.9495
= 0.0505
b)
We expect, 0.0505 * 98 = 5 bottles containing more than 32.49 oz. of ale.
2)
P(X < 16) = 0.02
P(Z < ( x - ) / ) = 0.02
From Z table, z-score for the probability of 0.02 is -2.0537
( x - ) / ) = -2.0537
( 16 - ) / 2 = -2.0537
= 20.1
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