Ho: M= 9
Ha: M > 9
Data: 9, 4 , 5 , 6 , 12, 23, 18, 19, 10, 12, 6, 11, 8, 4, 5, 7, 7, 8, 13, 14, 15, 3, 1, 0, 17, 5
H0: M=9
Ha: M >9
Since n <30, we will use a one tailed t -test to test the hypothesis.
The test statistic is given by
is the sample mean
s is the samlpe standard deviation
n is the sample size
= 9.31
= 5.82
Using the above values, test statistic t is
t = 0.27
We use the t table to find the t critical value.
Assuming a signifcance level of 5% with df = n -1 = 26-1=25 and one tailed test,
p -value ~ 0.6
Since p-value > 0.05 , we cannot reject the null hypothesis.
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