Question

CRA CDs Inc. wants the mean lengths of the “cuts” on a CD to be 158...

CRA CDs Inc. wants the mean lengths of the “cuts” on a CD to be 158 seconds (2 minutes and 38 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10-minute segment. Assume the distribution of the length of the cuts follows a normal distribution with a standard deviation of fourteen seconds. Suppose that we select a sample of 24 cuts from various CDs sold by CRA CDs Inc. Use Appendix B.1 for the z-values.

a. What can we say about the shape of the distribution of the sample mean?

Sample mean             (Click to select)  Normal  Uniform  Binomial

b. What is the standard error of the mean? (Round the final answer to 2 decimal places.)

Standard error of the mean             seconds.

c. What percentage of the sample means will be greater than 162 seconds? (Round the final answer to 2 decimal places.)

Sample means             %

d. What percentage of the sample means will be greater than 150 seconds? (Round the final answer to 2 decimal places.)

Sample means             %

e. What percentage of the sample means will be greater than 150 but less than 162 seconds? (Round the final answer to 2 decimal places.)

Sample means             %

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
CRA CDs Inc. wants the mean lengths of the “cuts” on a CD to be 148...
CRA CDs Inc. wants the mean lengths of the “cuts” on a CD to be 148 seconds (2 minutes and 28 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10-minute segment. Assume the distribution of the length of the cuts follows a normal distribution with a standard deviation of eight seconds. Suppose that we select a sample of 26 cuts from various CDs sold by CRA CDs Inc. Use Appendix B.1 for...
CRA CDs Inc. wants the mean lengths of the “cuts” on a CD to be 150...
CRA CDs Inc. wants the mean lengths of the “cuts” on a CD to be 150 seconds (2 minutes and 40 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10- minute segment. Assume the distribution of the length of the cuts follows a normal distribution with a standard deviation of nine seconds. Suppose that we select a sample of 12 cuts from various CDs sold by CRA CDs Inc. What percentage of...
CRA CDs, Inc. wants the mean lengths of the “cuts” on a CD to be 135...
CRA CDs, Inc. wants the mean lengths of the “cuts” on a CD to be 135 seconds (2 minutes and 15 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10-minute segment. Assume the distribution of the length of the cuts follows the normal distribution with a standard deviation of 8 seconds. Suppose we select a sample of 100 cuts from various CDs sold by CRA CDs, Inc. 1. What is the standard...
CRA CDs, Inc. wants the mean lengths of the “cuts” on a CD to be 135...
CRA CDs, Inc. wants the mean lengths of the “cuts” on a CD to be 135 seconds (2 minutes and 15 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10-minute segment. Assume the distribution of the length of the cuts follows the normal distribution with a standard deviation of 8 seconds. Suppose we select a sample of 100 cuts from various CDs sold by CRA CDs, Inc. What can we say about...
Majesty Video Production INC wants the mean length of its advertisements to be 34 seconds. Assume...
Majesty Video Production INC wants the mean length of its advertisements to be 34 seconds. Assume the distribution of the ad length follows the normal distrubution with a population standard deviation of 2 seconds. Supposed we select a sample of 13 ads produced by Majesty. What can we say about the shape of the distribution of the sample mean time? What is the standard error of the mean time? (Round to 2 decimal places) What percent of the sample means...
Majesty Video Production Inc. wants the mean length of its advertisements to be 32 seconds. Assume...
Majesty Video Production Inc. wants the mean length of its advertisements to be 32 seconds. Assume the distribution of ad length follows the normal distribution with a population standard deviation of 2 seconds. Suppose we select a sample of 20 ads produced by Majesty. What can we say about the shape of the distribution of the sample mean time? What is the standard error of the mean time? (Round your answer to 2 decimal places.) What percent of the sample...
Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume...
Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad length follows the normal distribution with a population standard deviation of 2 seconds. Suppose we select a sample of 18 ads produced by Majesty. What can we say about the shape of the distribution of the sample mean time? What is the standard error of the mean time? (Round your answer to 2 decimal places.) What percent of the sample...
Majesty Video Production Inc. wants the mean length of its advertisements to be 29 seconds. Assume...
Majesty Video Production Inc. wants the mean length of its advertisements to be 29 seconds. Assume the distribution of ad length follows the normal distribution with a population standard deviation of 2 seconds. Suppose we select a sample of 17 ads produced by Majesty. What can we say about the shape of the distribution of the sample mean time? What is the standard error of the mean time? (Round your answer to 2 decimal places.) What percent of the sample...
Majesty Video Production Inc. wants the mean length of its advertisements to be 29 seconds. Assume...
Majesty Video Production Inc. wants the mean length of its advertisements to be 29 seconds. Assume the distribution of ad length follows the normal distribution with a population standard deviation of 2 seconds. Suppose we select a sample of 17 ads produced by Majesty. What can we say about the shape of the distribution of the sample mean time? What is the standard error of the mean time? (Round your answer to 2 decimal places.) What percent of the sample...
Majesty Video Production Inc. wants the mean length of its advertisements to be 24 seconds. Assume...
Majesty Video Production Inc. wants the mean length of its advertisements to be 24 seconds. Assume the distribution of ad length follows the normal distribution with a population standard deviation of 2 seconds. Suppose we select a sample of 12 ads produced by Majesty. What can we say about the shape of the distribution of the sample mean time? a) What can we say about the shape of the distribution of the sample mean time? Normal, skewed? b)What is the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT