Question

Anova: Single Factor | |||||||

SUMMARY | |||||||

Groups | Count | Sum | Average | Variance | |||

Column 1 | 5 | 459 | 91.8 | 36.7 | |||

Column 2 | 5 | 410 | 82 | 51.5 | |||

Column 3 | 5 | 485 | 97 | 2939.5 | |||

ANOVA | |||||||

Source of Variation | SS | df | MS | F | P-value | F crit | |

Between Groups | 580.1333333 | 2 | 290.0666667 | 0.287412888 | 0.755224 | 3.885293835 | |

Within Groups | 12110.8 | 12 | 1009.233333 | ||||

Total | 12690.93333 | 14 |

Answer #1

SUMMARY
Groups
Count
Sum
Average
Variance
Dept. 1
10
340005
34000.5
31479782.94
Dept. 2
8
300391
37548.875
82885830.98
Dept. 3
7
284654
40664.85714
133792262.8
Dept.
4
21
907010
43190.95238
157721269.9
ANOVA
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
623553563.8
3
207851187.9
1.81088925
0.159863
2.827049
Within Groups
4820697839
42
114778520
Total
5444251403
45
Using this data, please answer if there are significant salary
differences between the four departments? Please
provide evidence to support your conclusion.

How do I know whether the variable of interest exhibit a
statistical significant difference between the groups?
Anova: Single Factor
SUMMARY
Groups
Count
Sum
Average
Variance
Column 1
22
1420318
64559.90909
83671674.28
Column 2
15
1295223
86348.2
72184280.89
Column 3
13
2145812
165062.4615
10933748061
ANOVA
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
85073726515
2
42536863258
14.92269054
9.60024E-06
3.19505628
Within Groups
1.33973E+11
47
2850482167
Total
2.19046E+11
49

There is a statistical difference between groups as the p-value
is less than 5%. Do I need to perform a post-hoc test? Why or why
not?
SUMMARY
Groups
Count
Sum
Average
Variance
Column 1
22
1420318
64559.90909
83671674.28
Column 2
15
1295223
86348.2
72184280.89
Column 3
13
2145812
165062.4615
10933748061
ANOVA
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
85073726515
2
42536863258
14.92269054
9.60024E-06
3.19505628
Within Groups
1.33973E+11
47
2850482167
Total
2.19046E+11
49

You are given the following ANOVA Single-factor
output.
Groups
Count
Sum
Average
Variance
1
3.00
166.00
55.33
156.33
2
3.00
213.00
71.00
444.00
3
3.00
197.00
65.67
114.33
4
3.00
219.00
73.00
508.00
5
3.00
235.00
78.33
786.33
6
3.00
160.00
53.33
92.33
7
3.00
256.00
85.33
10.33
8
3.00
206.00
68.67
574.33
9
3.00
210.00
70.00
333.00
10
3.00
290.00
96.67
2.33
ANOVA
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
4527.20
9.00
503.02
1.66...

An ANOVA test was conducted and the following results
were obtained.
Descriptive Statistics
Groups
Count
Sum
Average
Variance
A
244
109831
450.13
16833.16
B
1337
689273
515.54
13858.67
C
1060
641232
604.94
12652.42
ANOVA
Source of Variation
SS
df
MS
F
P-value
Between Groups
7164292.02
2
3582146.01
262.46
0.000
Within Groups
36004549.12
2638
13648.43
Total
43168841.14
2640
What would be the Type I error rate if a series of
t-tests were performed instead of the ANOVA test?...

6. (36 pts) The following is an incomplete
ANOVA summary table:
Source
df
SS
MS
F
Among Groups
3
63
Within Groups
16
97
Total
(a) Complete the ANOVA summary table.
(b) Determine the number of groups.
(b) At the α = 0.05 level of significance, determine whether
there is evidence of difference in the population means.

The following is the sample information. Test the hypothesis at
the 5% level of significance that the treatment means are equal.
Present your solution by the p value method
Treatment 1
Treatment 2
Treatment 3
9
13
10
7
20
9
11
14
15
9
13
14
12
15
10
Anova: Single Factor
SUMMARY
Groups
Count
Sum
Average
Variance
Treatment 1
6
58
9.66666667
3.066667
Treatment 2
4
60
15
11.33333
Treatment 3
5
63
12.6
8.3
ANOVA
Source...

Complete the following ANOVA summary table. There are seven
groups of plants receiving different fertilizer treatments, each
with 24 samples. Use a significance level of α=0.10
Source
SS
df
MS
F
P
Between
124.875
Within
TOTAL
1511.085

Please read
carefully. You must show all of your work for full
credit. A correct answer with no work shown is worth no
points, but an incorrect or partial answer with some work shown may
be worth partial credit
I. The following
ANOVA are from an experiment designed to investigate the perception
of corporate ethical values among individuals specializing in
marketing.
Anova: Single Factor
SUMMARY
...

A one-way analysis of variance experiment produced the following
ANOVA table. (You may find it useful to reference
the q table).
SUMMARY
Groups
Count
Average
Column 1
6
0.71
Column 2
6
1.43
Column 3
6
2.15
Source of Variation
SS
df
MS
F
p-value
Between Groups
10.85
2
5.43
20.88
0.0000
Within Groups
3.86
15
0.26
Total
14.71
17
SUMMARY
Groups
Count
Average
Column 1
6
0.71
Column 2
6
1.43
Column 3
6
2.15
ANOVA
Source of Variation...

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