Which of the following functions are probability mass functions? For those that are not, find (if possible) a constant a so that a · p(ω) is a probability mass function.
a. p(ω) = ω 2 55 , ω = 1, 2, 3, 4, 5
b. p(ω) = 1 3 2 3 ω , ω = 3, 4, 5, 6, . . .
c. p(ω) = 1 for each ω in a nine-member set Ω.
d. p(ω) = 1 for each ω in a countably infinite set Ω.
e. p(ω) = ω, ω = 1, 2, 3, 4, . . . , N
f. p(ω) = 1 4 ω , ω = 0, 1, 2, 3, 4, . . .
g. p(ω) = 1 ω , ω = 1, 2, 3, 4, . . .
h. p(ω) = 1 3 (ω − 2), ω = 0, 1, 2, 3, 4
Answer:
a) p(w) = w^2/55 = ( 1+4+9+16+25)/55 = 55/55 = 1 Yes it is PMF
b) p(w) = (1/3)(2/3)^w = (1/3)(2/3)^3+(1/3)(2/3)^4+(1/3)(2/3)^5+(1/3)(2/3)^6+........Its a GP
= (1/3)(2/3)^3 / (1 -2/3)
= 1/3 * 8/27 * 3
=8/27 : Not a PMF , a = 27/8
c) p(w) =1 Not a pmf , a = 1/9
Explanation: It is actually for nine members : (1+1+1+1+1+1+1+1+1) = 9
Hence a =1/9 is chosen to make it as 1.
d) p(w) =1 Not a pmf , a = 1/N
Explanation: It is actually for countably infinite , so let N be the count : (1+1+1+1+1+1+1+1+1+........+1)----> N times = N
e) p(w) = w
= 1+2+3+4,.......N
= N+1
f) p(w) = (1/4)^w
= from b we can conclude f is also not a PMF
g) p(w) = 1/w
= 1/1+1/2+1/3 + 1/4....
= not a PMF
h) p(w) = 1/3(w-2)
= 1/3(0-2)+ 1/3(1-2)+ 1/3(2-2)+ 1/3(3-2)+ 1/3(4-2)
= -2/3+-1/3+0+2/3
=1/3
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