. Ace Taxi divides a city into two zones:A and B. If a driver picks up a client in A, he will drop them off in A with probability 0.25 and drop them off in B with probability 0.75. If a driver picks up a client in zone B, he will drop them off in zone A with chance 0.4 and drop them off in zone B with chance 0.6. The company rules dictate that a driver must remain in a given zone for the next client.
(a) Given that the driver starts in zone A compute the probabilities that the driver will be in zones B after two clients have been served.
(b) Given that the driver starts in zone B compute the probabilities that the driver will be in zones A after two clients have been served.
We know that if a driver picks up a client in zone A, he drops them in A with probability 0.25 and drops them in B with probability 0.75.
We know that if a driver picks up a client in zone B, he drops them in A with probability 0.4 and drops them in B with probability 0.6.
a.
We know that the driver starts in zone A.
Thus, we must find the P(B | starts in A)
There are two ways this can go:
1. He gets the first ride in A.
= 0.25*0.75
= 0.1875
2. He gets the first ride in B.
= 0.75*0.60
= 0.45
Thus, the required probability is 0.1875+0.45
= 0.6375
b.
We know that the driver starts in zone B.
Thus, we must find the P(A | starts in B)
There are two ways this can go:
1. He gets the first ride in A.
= 0.4*0.25
= 0.10
2. He gets the first ride in B.
= 0.60*0.40
= 0.24
Thus, the required probability is 0.10+0.24
= 0.34
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