7.
(07.02 MC)
Oscar, a yoga instructor at Yoga for You, is interested in comparing levels of physical fitness of students attending a nearby high school and those attending a local community college. He selects a random sample of 210 students from the high school. The mean and standard deviation of their fitness scores are 82 and 14, respectively. He also selects a random sample of 210 students from the local community college. The mean and standard deviation of their fitness scores are 86 and 17, respectively. He then conducts a two-sided t-test that results in a t value of 2.63. Which of the following is an appropriate conclusion from this study when α = 0.05? (4 points)
Because the sample means only differ by four, the population means are not significantly different. |
|
Because the second group has a larger standard deviation, their mean fitness score is significantly higher. |
|
Because the second group has a larger standard deviation, the mean fitness score of the first group is significantly higher. |
|
Because the p-value is greater than α = 0.05, the mean fitness scores for the two groups of students are not significantly different. |
|
Because the p-value is less than α = 0.05, the mean fitness scores for the two groups of students are significantly different. |
8.
(07.02 LC)
A student working on a report about mathematicians decides to find the 98% confidence interval for the difference in mean age at the time of math discovery for Greek mathematicians versus Egyptian mathematicians. The student finds the ages at the time of math discovery for members of both groups, which include all Greek and Egyptian mathematicians, and uses a calculator to determine the 98% confidence interval based on the t distribution. Why is this procedure not appropriate in this context? (4 points)
The sample sizes for the two groups are not equal. |
|
Age at the time of math discovery occurs at different intervals in the two countries, so the distribution of ages cannot be the same. |
|
Ages at the time of math discovery are likely to be skewed rather than bell shaped, so the assumptions for using this confidence interval formula are not valid. |
|
Age at the time of math discovery is likely to have a few large outliers, so the assumption for using this confidence interval formula is not valid. |
|
The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used. |
9.
(07.02 LC)
The manager of a computer repair shop wants to compare the mean number of motherboard repairs in a week for two repair techniques. Twenty-four technicians from the shop are selected randomly, and each technician is assigned randomly to one of the two techniques. After teaching 12 technicians one technique and 12 technicians the other technique, the manager records the number of motherboard repairs each technician performs in one week. Which of the following is the MOST appropriate inferential statistical test in this situation? (5 points)
A one-sample z-test |
|
A paired t-test |
|
A two-sample t-test |
|
A chi-square goodness-of-fit test |
|
A one-sample t-test |
10.
(07.02 LC)
Randall is conducting a test on bacteria on slices of cheese. He
uses 10 slices of cheese to compare two strains of bacteria. He
applies one strain to the left side of the cheese and one strain to
the right side. He flips a coin to decide which strain goes on the
right side of the cheese. The bacteria holes that appear on each
side are counted and he records them in a table.
Cheese | Number of Holes for Strain 1 | Number of Holes for Strain 2 |
---|---|---|
1 |
25 |
19 |
2 |
21 |
15 |
3 |
13 |
14 |
4 |
13 |
12 |
5 |
14 |
10 |
6 |
12 |
9 |
7 |
11 |
5 |
8 |
11 |
5 |
9 |
8 |
4 |
10 |
5 |
4 |
If Randall is to perform an appropriate t-test to determine if
there is a difference in the mean number of holes per slice of
cheese produced by the two strains, how many degrees of freedom
should he use? (4 points)
7 |
|
8 |
|
9 |
|
10 |
|
18 |
11.
(07.05 MC)
In a study of the performance of a tires, the width of tires (in inches) and the life span (in months) for 14 tires were recorded. A regression line was a satisfactory description of the relationship between width of tire and tire life span. The results of the regression analysis are shown in the table.
Variable | Coeff | SE Coeff | t Ratio | p-Value |
---|---|---|---|---|
Constant | 7.3985 | 0.5638 | 13.12 | 0.034 |
Width of tires | 3.9571 | 0.7382 | 5.36 | 0.005 |
R squared = 88.5% |
R squared (adj) = 87.9% |
Which of the following should be used to compute a 98% confidence interval for the slope of the regression line? (5 points)
7.3985 ± 2.681(0.5638) |
|
7.3985 ± 2.624(0.5638) |
|
3.9571 ± 2.65(0.7382) |
|
3.9571 ± 2.624(0.7382) |
|
3.9571 ± 2.681(0.7382) |
12.
(07.05 LC)
The weight (in pounds) and the number of offspring of 23 randomly selected rabbits are compared. Which significance test should be used to determine whether a linear relationship exists between weight and number of offspring, provided the assumptions of the test are met? (4 points)
A two-sample z-test |
|
A two-sample t-test |
|
A t-test for the slope of the regression line |
|
A chi-square test of independence |
|
A chi-square goodness-of-fit test |
7)
n1 = 210
n2 = 210
Degrees of freedom = n1 + n2 - 2 = 418
Level of significance = 0.05
Test statistic = t = 2.63
Our test is two-sided t-test.
P-value = 2*P(T > 2.63) = 0.0089
Conclusion:
Because the p-value is less than α = 0.05, the mean fitness scores for the two groups of students are significantly different.
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