Question

Assume that in an apple orchard the heights of the trees are
normally distributed with a mean of 14 feet and a standard
deviation of 3 feet. Show all work for the following
problems.

(a) What is the probability that a randomly selected tree is at
least 7 feet tall?

(b) What is the probability that a randomly selected tree is
between 14 and 16 feet tall?

Round answers to 4 decimal places.

Answer #1

**Solution:**

(a)

(b)

The heights of pecan trees are normally distributed with
a mean of 10 feet and a standard deviation of 2 feet.
13.Show all work. Just the answer, without supporting
work, will receive no credit.
(a)What is the probability that a randomly selected pecan tree
is between 9 and 12 feet tall?
(b)Find the 75th percentile of the pecan tree height
distribution.

The heights of pecan trees are normally distributed with a mean
of 10 feet and a standard deviation of 2 feet. 13. Show all
work. Just the answer, without supporting work, will
receive no credit.
(a) What is the probability that a randomly selected pecan tree
is between 9 and 12 feet tall? (Round the answer to 4 decimal
places)
(b) Find the 75th percentile of the pecan tree height
distribution. (Round the answer to 2 decimal places)
(c) For...

Cherry trees in a certain orchard have heights that are normally
distributed with mean μ = 109 inches and standard deviation σ = 11
inches. Use the Cumulative Normal Distribution Table to answer the
following.
(a) Find the 23 rd percentile of the tree heights.
(b) Find the 81 st percentile of the tree heights.
(c) Find the second quartile of the tree heights.
(d) An agricultural scientist wants to study the tallest 2 % of
the trees to determine...

3. Assume that oak trees have an average height of 90 feet with
a standard
deviation of 14 feet. Their heights are normally distributed
(i.e., μ = 90 and σ = 14).
A. Using a z table determine the percent of oak trees that are
at least 106.50 feet tall. (Hint: You will need to start by
converting 106.50 to a z score.)
B. Using a z table determine the percent of oak trees that are
83.95 feet or less....

The heights of fully grown trees of a specific species are
normally distributed, with a mean of 72.5 feet and a standard
deviation of 7.50 feet. Random samples of size 15 are drawn from
the population. Use the central limit theorem to find the mean and
standard error of the sampling distribution. Then sketch a graph of
the sampling distribution.

Assume that the heights of women are normally distributed with a
mean of 63.6 inches and a standard deviation of 2.5 inches. a) Find
the probability that if an individual woman is randomly selected,
her height will be greater than 64 inches. b) Find the probability
that 16 randomly selected women will have a mean height greater
than 64 inches.

The heights of fully grown trees of a specific species are
normally distributed, with a mean of 61.0 feet and a standard
deviation of 6.00 feet. Random samples of size 19 are drawn from
the population. Use the central limit theorem to find the mean and
standard error of the sampling distribution. Then sketch a graph of
the sampling distribution. The mean of the sampling distribution is
?. The standard error of the sampling distribution is ?

Suppose that the heights of adult men in the United States are
normally distributed with a mean of 69 inches and a standard
deviation of
3 inches. What proportion of the adult men in United States are
at least 6 feet tall? (Hint: 6 feet =72 inches.) Round your answer
to at least four decimal places.

The heights of adult men in America are normally distributed,
with a mean of 69.6 inches and a standard deviation of 2.63 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.2 inches and a standard
deviation of 2.56 inches.
a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
z =
b) If a woman is 5 feet 11 inches tall, what is...

The heights of adult men in America are normally distributed,
with a mean of 69.8 inches and a standard deviation of 2.66 inches.
The heights of adult women in America are also normally
distributed, but with a mean of 64.4 inches and a standard
deviation of 2.56 inches.
a) If a man is 6 feet 3 inches tall, what is his z-score (to two
decimal places)?
z = .........
b) If a woman is 5 feet 11 inches tall, what...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 29 minutes ago

asked 36 minutes ago

asked 51 minutes ago

asked 51 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago