The sample size needed to estimate a population mean to within
50 units was found to be 97. If the population standard deviation
was 250, then the confidence level used was:
a) 90%
b) 95%
c) 98%
d) 99%
e) None of the above.
Solution :
Given that,
standard deviation = = 250
margin of error = E = 50
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Sample size = n = ((Z/2 * ) / E)2
= ((1.96 * 250) / 50)2
= 97
Sample size = 97
Confidence level = 95%
Option b) is correct .
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