Question

You are the new Defense Against the Dark Arts professor at the Hogwarts School of Witchcraft...

You are the new Defense Against the Dark Arts professor at the Hogwarts School of Witchcraft and Wizardry. You are a member of one of the four Houses yourself (Gryffindor, Slytherin, Ravenclaw, or Hufflepuff) and you think that students in your House are better than students in any of the other Houses. But you want to conduct an experiment to know for sure. So you set up a giant obstacle course that your students have to get through. The number of monsters the students defeat before breaking down in tears is your dependent variable and House membership is your factor.

Gryffindor: M = 4, SD = 1 Slytherin: M = 5.5, SD = 1.29 Ravenclaw: M = 3.67, SD = 2.08. Hufflepuff: M = 3.5, SD = 1.29.

Here is the ANOVA summary table:

Source

SS

df

MS

Between

9.6905

3

3.2302

F(3, 10) = 1.56

Within

20.6667

10

2.0667

Total

30.3571

13

--

21. Make a decision regarding the null hypothesis and state whether House membership affects the number of monsters defeated (you’ll need to find F-critical first).

22. Would you conduct post-hoc tests on these data? Why or why not?

Homework Answers

Answer #1

2.1)

F-critical = 3.71

F stat = 1.56

F stat < f critical , do not reject Ho

so, house membership do not effect the number of monster defeated

.................

2.2)

no need of conducting post hoc test

as there is no difference between groups

post hoc test is done to know where the differences lie

-------------------------------------

DEAR STUDENT,

IF YOU HAVE ANY QUERY ASK ME IN THE COMMENT BOX,I AM HERE TO HELPS YOU.PLEASE GIVE ME POSITIVE RATINGS

*****************THANK YOU***************

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT