Women |
Men |
|
n |
16 |
25 |
X¯ |
$26.4 |
$33.3 |
S |
$2.6 |
$3.2 |
Test H0 : µ1 = µ2 against H1 : µ1 = µ2 where µ1 and µ2 are the mean salary of first level female and
male managers, respectively. Use α = 0.05 and assume equal variances.
a |
|
|
b |
Test statistic = −2.68 and fail to reject H0 |
|
c |
|
|
d |
|
To test
test statistic is given by
t = -7.22
Decison criteria : Reject Ho if | test statistic | > critical t value
critical t value with n1 + n2 -2 degrees of freedom and level of significance =
since it is a two tailed test we consider
with degrees of freedom 16 + 25 - 2 = 39
critical t = 2.023
therefore | - 7.22 | = 7.22 > 2.023
Reject the null hypothesis
option c is correct
Test statistic = -7.22 , Reject Ho
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