The allowable stress X of a mechanical component is normally distributed, X ∼ N(120, 20) MPa , and the maximum stress y is normally distributed, y ∼ N(100, 10) MPa .
a) What is the probability of failure pf ?
b) What is standard deviation of failure σf ?
a)
The mechanical component will fail if Y will be greater than X. Since X and Y both are normally distributed so the distribution o Y-X will be normally distributed with mean and SD follows:
and
The z-score for Y-X = 0 is
The probability of failure is
P(Y-X > 0) = P(z > -0.89) = 1 - P(z <= -0.89) = 1 - 0.1867 = 0.8133
b)
The standard deviation of failure σf is
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