Suppose that 50% of adult Australians believe that Australia should apply to host the next rugby World Cup. Calculate the probability that more than 56% of a random sample of 150 adult Australians would believe this.
Here we assume that 50% of adult Australians believe that Australia should apply to host the next rugby World Cup.
Let P = 0.50
And we want to find the probability that more than 56% of a random sample of 150 adult Australians would believe this.
Mathematically,
P( P > 0.56) = 1 - P( P < 0.56) ....( 1 )
Here n = 150 which is very large and we can use normal approximation to find the probability.
The mean and standard deviation of sample proportion are as follows.
mean = = P = 0.50
Standard deviation =
Let's use excel:
P( P < 0.56) = "=NORMDIST(0.56,0.5,0.040825,1)" = 0.929177
Plug this value in equation ( 1 ), we get
P( P > 0.56) = 1 - 0.929177 = 0.070823 ( This is the final answer).
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