To estimate the mean of a normal population whose standard deviation is 6, with a bound on the error of estimation equal to 1.2 and confidence level 99% requires a sample size of at least:
a.166b
b.167
c.13
d.None of these choices
Solution :
Given that,
standard deviation = = 6
margin of error = E = 1.2
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Sample size = n = ((Z/2 * ) / E)2
= ((2.576 * 6) / 1.2)2
= 165.8 = 166b
Sample size = 166b
option a) is correct
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