The following table shows the approximate number of males of Hispanic origin employed in the United States in a certain year, broken down by age group.
Age | 15-24.9 | 25-54.9 | 55-64.9 |
---|---|---|---|
Employment (thousands) | 25,000 | 16,000 | 1,000 |
(a) Use the rounded midpoints of the given measurement classes to compute the expected value and the standard deviation of the age X of a male Hispanic worker in the United States. (Round all probabilities and intermediate calculations to two decimal places.)
expected value | yrs old |
standard deviation | yr |
(b) In what age interval does the empirical rule predict that 68
percent of all male Hispanic workers will fall? (Round answers to
the nearest year.)
a)
Midpoint = (Lower limit + upper limit )/ 2
For interval, 15-24.9, midpoint = 15 + 24.9 / 2 = 19.95
For interval 25-54.9, midpoint = 25 + 54.9 / 2 = 39.95
For interval 55- 64.9 , midpoint= 55 + 64.9 / 2 = 59.95
Let X be midpoint and Employment be f
Then,
E(X) = X * f / f
= 19.95 * 25000 + 39.95 * 16000 + 59.95 * 1000 / (25000 + 16000 + 1000)
= 28.52
Standard deviation = Sqrt [ ( x2f - n * mean2 ) / n -1 ] Where n = f
= Sqrt[ 19.952 * 25000 + 39.952 * 16000 + 59.952 * 10000 - 51000 * 28.522 / 50999)]
= 10.82
b)
according to emperical rule,
Approximately, 68% data falls between 1 standard deviation of the mean.
Range = (Mean - standard deviation , Mean + standard deviation)
= (28.52 - 10.82 , 28.52 + 10.82 )
= (18 , 39)
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