A data set includes data from student evaluations of courses. The summary statistics are n=939, x=3.43, s=0.52.Use a 0.01significance level to test the claim that the population of student course evaluations has a mean equal to 3.50 Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
H0: = 3.50
Ha: 3.50
Test statistics
t = ( - ) / (S / sqrt(n) )
= (3.43 - 3.50) / (0.52 / sqrt(939) )
= -4.125
This is test statistics value.
df = n - 1 = 939 - 1 = 938
From T table,
t critical value at test statistics 4.125 and df of 938,
p-value = 0.0000
Since p-value < 0.01 level, reject the null hypothesis.
We conclude at 0.01 level that we have sufficient evidence to support the claim that the population of student course
evaluations has a mean equal to 3.50 .
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