A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population).
x1: New England Crime Rate
Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population).
x2: Rocky Mountain Crime Rate
Assume that the crime rate distribution is approximately normal in both regions. Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.)
What is the value of the sample test statistic? Compute the
corresponding z or t value as appropriate. (Test
the difference μ1 − μ2. Do not use rounded
values. Round your answer to three decimal places.)
(b) Find a 98% confidence interval for
μ1 − μ2.
(Round your answers to two decimal places.)
|std error =√(S21/n1+S22/n2)=||0.380|
|test stat t =(x1-x2-Δo)/Se =||-0.832|
|Point estimate of differnce =x1-x2 =||-0.317|
|for 98 % CI & 9 df value of t=||2.821|
|margin of error E=t*std error =||1.073|
|lower bound=mean difference-E =||-1.39|
|Upper bound=mean differnce +E =||0.76|
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