You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the population proportion. You would like to be 90% confident that your estimate is within 0.1% of the true population proportion. How large of a sample size is required?
Solution :
Given that,
= 0.5 ( when estimate is not given then use 0.5)
1 - = 1 - 0.5 = 0.5
margin of error = E = 0.01% = 0.0001
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
Sample size = n = (Z/2 / E)2 * * (1 - )
= (1.645 */0.0001)2 * 0.5 *0.5
=67650625
Sample size = 67650625
Get Answers For Free
Most questions answered within 1 hours.