The typical amount of sleep per night for college graduate students has a normal
distribution with a mean of 5 hours. What is the standard deviation of this distribution if
16% of students sleep more than 6.5 hours?
A.
1.52
B.
-1.55
C.
-1.52
D.
1.55
Solution:-
Given that,
mean = = 5 hours
x = 6.5 hours
Using standard normal table,
P(Z > z) = 16%
= 1 - P(Z < z) = 0.16
= P(Z < z) = 1 - 0.16
= P(Z < z ) = 0.84
= P(Z < 0.99 ) = 0.84
z = 0.99
Using z-score formula,
x = z * +
6.5 = 0.99 * + 5
= 6.5 - 5 / 0.99
= 1.52
correct option is = A
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