Question

The golf scores for a school team were normally distributed with a mean =68 and a standard deviation=3

1. Determine the z for a golfer who scored 65
2. Find the probability that a randomly selected golfer scored less than 65
3. Find the probability that a randomly selected golfer scored between 60 and 70

Answer 1

#X=score of gloper

x~Normal distribution

=68

=3

a) z when X=65

Z=(x-)/

Z=(65-68)/3

z=-1

b)p(X<65)=P(z<-1)

=0.1587

#probability that a randomly selected golfer scored less than 65=0.1587

C) p(60<X<70)=((60-68)/3<(x-)/<(70-68)/3)

=P(-2.67<z<0.67)

=P(z<0.67)-P(z<-2.67)

=0.7475-0.0038

=0.7437

#the probability that a randomly selected golfer scored between 60 and 70 is 0.7437