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The length of a particular metal bar used in the construction of your chair is normally distributed with a mean m of 3 meters and a standard deviation of s = .2 meters, then:
a) What is the probability that the average of 4 bars selected at random from this process will be less than 2.90 meters?
b) What is the probability that the average of 4 bars selected at random from this process will be between 2.90 meters and 3.1 meters?
Let's consider X be the length of a particular metal bar used in the construction.
Therefore,
a) The probability that the average of 4 bars selected at random from this process will be less than 2.90 meters is given by
### By using Z table or can use R command >pnorm(-1,0,1)
b) The probability that the average of 4 bars selected at random from this process will be between 2.90 meters and 3.1 meters is given by:
### By using Z table
he probability that the average of 4 bars selected at random from this process will be between 2.90 meters and 3.1 meters is 0.6826
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