Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of a national park. The deer counts per square kilometer were recorded and are shown in the following table.
Mountain Brush | Sagebrush Grassland | Pinon Juniper |
34 | 20 | 3 |
26 | 56 | 12 |
18 | 17 | 9 |
31 | 22 | 7 |
(b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.)
SSTOT | = | |
SSBET | = | |
SSW | = |
Find d.f.BET, d.f.W,
MSBET, and MSW. (Use 2 decimal
places for MSBET, and
MSW.)
dfBET | = | |
dfW | = | |
MSBET | = | |
MSW | = |
Find the value of the sample F statistic. (Use 3 decimal
places.)
What are the degrees of freedom?
(numerator)=
(denominator)=
(f) Make a summary table for your ANOVA test.
Source of Variation |
Sum of Squares |
Degrees of Freedom |
MS | F Ratio |
P Value | Test Decision |
Between groups | ---Select--- p-value > 0.100 0.050 < p-value < 0.100 0.025 < p-value < 0.050 0.010 < p-value < 0.025 0.001 < p-value < 0.010 p-value < 0.001 | ---Select--- Do not reject H0. Reject H0. | ||||
Within groups | ||||||
Total |
I have done the above data in spss using one way anova
Step 1 : Entered the values in the data view
Step 2 : Analyze - > compare means -> one way anova .
Output is as follows :
1 ) SSTOT = 2290.250
SSBET=1098.000
SSW=1192.250
HENCE,SSTOT=SSBET+SSW
2 ) df.BET = 2
dfW=9
MSBET=549
MSW=132.47
3)VALUE OF F STATISTIC = 4.144
SINCE F=MSBET/MSW
Numerator df =2
Denominator df = 9
Source of variation | Sum of squares | df | MS | F ratio | p value | Test decision |
Between groups | 1098.000 |
2 |
549.00 | 4.144 |
0.053 ,which is greater than 0.05 0.05<pvalue<0.1 |
Hence we accept H0,that is there is no statistically difference between the 3 groups. |
Within groups | 1192.250 | 9 | 132.47 | |||
Total | 2290.250 | 11 |
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