Question

Consider the following data regarding students' college GPAs and high school GPAs. The estimated regression equation is Estimated College GPA=2.02+0.2752(High School GPA). Estimated College GPA = 2.02 + 0.2752 ( High School GPA ) . GPAs College GPA High School GPA 2.80 2.80 2.04 2.04 3.39 3.39 4.06 4.06 2.20 2.20 2.05 2.05 2.70 2.70 3.63 3.63 3.11 3.11 4.42 4.42 3.17 3.17 2.88 2.88 Step 3 of 3 : Compute the standard error (se s e ) of the model. Round your answer to four decimal places.

Answer 1

sr	x	y	(x-xbar)^2	(y-ybar)^2	(x-xbar)*(y-ybar)
1	2.04	2.8	1.2996	0.009025	0.1083
2	4.06	3.39	0.7744	0.245025	0.4356
3	2.05	2.2	1.2769	0.483025	0.78535
4	3.63	2.7	0.2025	0.038025	-0.08775
5	4.42	3.11	1.5376	0.046225	0.2666
6	2.88	3.17	0.09	0.075625	-0.0825
sum	19.08	17.37	5.181	0.89695	1.4256
mean	3.18	2.895	SXX	SYY	Sxy
	slope=sxy/sxx	0.275159236		14.30828
	intercept=ybar-(slope*xbar)	2.019993631		16.328274
		sxy^2/sxx	0.392267
	SSE	syy-sxy^2/sxx	0.504683
	error variance  2	s2=SSE/(n-2)	0.1009366
	Se	se=s2	0.3177

#standard error =0.3177