Question

Compute the expectation of SS(Treatment) under the assumption that τi’s are equal in the context of one-way layout.

Answer #1

The following is sample information. Test the hypothesis that
the treatment means are equal. Use the 0.02 significance level.
Treatment 1
Treatment 2
Treatment 3
7
2
5
8
3
7
6
5
10
7
3
6
a. State the null hypothesis and the alternate
hypothesis.
H0:
(The treatment
means are not all the same or The treatment means are the
same?)
H1:
(The treatment
means are not all the same or The treatment means are...

The following is sample information. Test the hypothesis that
the treatment means are equal. Use the 0.02 significance level.
Treatment 1
Treatment 2
Treatment 3
3
10
4
8
6
6
3
9
3
5
7
10
a. State the null hypothesis and the alternate
hypothesis.
H0:
(Click to
select) The treatment means are not all the
same. The treatment means are the same.
H1:
(Click to
select) The treatment means are the same. The
treatment means are not all...

The following is sample information. Test the hypothesis that
the treatment means are equal. Use the 0.01 significance level.
Treatment 1
Treatment 2
Treatment 3
10
7
8
8
8
7
6
8
6
9
4
8
a. State the null hypothesis and the alternate
hypothesis.
H0:
(Click to
select) The treatment means are the same. The
treatment means are not all the same.
H1:
(Click to
select) The treatment means are the same. The
treatment means are not all...

The following is sample information. Test the hypothesis that
the treatment means are equal. Use the 0.01 significance level.
Treatment 1
Treatment 2
Treatment 3
10
4
3
4
5
5
9
5
6
7
9
6
a. State the null hypothesis and the alternate
hypothesis.
H0:
(Click to
select) The treatment means are not all the
same. The treatment means are the same.
H1:
(Click to
select) The treatment means are the same. The
treatment means are not all...

Gender
Treatment Condition
Control MBSR
F 28,
24 12,
8
M 14,
10 14,
18
1. Compute SS(total), SS(within),
SS(between-overall) using a 2-way ANOVA.
2. Suppose you treated the data from
this experiment as a one-way ANOVA with four groups (i.e.,
disregarding the factorial arrangement). How would the three sums
of squares terms you computed in b, c, and d compare to their
counterparts in the one-way approach? Be precise.

The following is sample information. Test the hypothesis that
the treatment means are equal. Use the 0.05 significance level.
Treatment 1
Treatment 2
Treatment 3
3
4
8
6
3
10
3
8
6
10
7
8
1. What is the decision rule? (Round the final answer to
2 decimal places.)
Reject H0 if the test statistic is greater
than ___________.
2. Compute SST, SSE, and SS total. (Round the final
answers to 3 decimal places.)
SST = ...

Consider the partially completed one-way ANOVA summary
table.
Source
SS
df
MS
F
Treatment
150
Error
17
Total
840
21
Using α = 0.05, the critical F-score for this ANOVA procedure
is ________.

Given the following sample information, test the hypothesis that
the treatment means are equal at the 0.05 significance level.
Treatment 1
Treatment 2
Treatment 3
3
9
6
2
6
3
5
5
5
1
6
5
3
8
5
1
5
4
4
1
7
4
6
4
(a) State the null hypothesis and the alternate hypothesis. Ho :
?1 (>, <, or =) incorrect ?2 = (<,>, or =) ?3. H1 :
Treatment means are not ___ all...

After rejecting the null hypothesis of equal treatments, a
researcher decided to compute a 95 percent confidence interval for
the difference between the mean of treatment 1 and mean of
treatment 2 based on the Tukey procedure. At α = .05, if
the confidence interval includes the value of zero, then we can
reject the hypothesis that the two population means are equal.
True
False
The error sum of squares measures the between-treatment
variability.
True
False
The experimentwise α for...

While conducting a
one-way ANOVA comparing 4 treatment samples with 5 observations per
treatment sample, computed value for SS(Total) = 66 and MS(Error) =
3 given.
Source
of
SS
d.f.
MS
Test Statistic
Variation
Treatment
.….
….
…..
……
Error
48
….
3
Total
66
What is the value of
F-test statistic using ANOVA table?
6
2
3
5

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