Question

2. In a survey of 2000 students, 1638 of them thought that the prices in the...

2. In a survey of 2000 students, 1638 of them thought that the prices in the school cafeteria were too high

2a. Find a point estimate for the proportion of the school that thinks the prices in the school cafeteria are to high.

2b. Which requirement might not be met here?

2c. Find a 90% confidence interval for the proportion of the school that thinks the prices in the school cafeteria are too high.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. A random sample of 640 adults in a large country was asked “Do you need...
1. A random sample of 640 adults in a large country was asked “Do you need a haircut?” Of the 640 adults surveyed, 283 indicated that they need a haircut. 1a. Check the requirements needed to construct a confidence interval for the population proportion. 1b. Find a 95% confidence interval for the population proportion of adults who need a haircut. 1c. Could exactly 25% of the country need a haircut? 2. In a survey of 2000 students, 1638 of them...
A survey of 16 randomly chosen students, 2 of them have a surfing board. Create a...
A survey of 16 randomly chosen students, 2 of them have a surfing board. Create a 90% confidence interval for the proportion of students who have a surfing board based on the survey. Please find the upper limit using R.
In a survey of 275 students, 32% of them admitted that they have texted while in...
In a survey of 275 students, 32% of them admitted that they have texted while in class, (a) Find x, the number of students that have texted while in class. x= (b) What is the best point estimate of the population proportion p(hat) = (b) Find the 98% confidence interval for the proportion of all students that have texted while in class. (c) CI ; Round to 3 decimal places
In a survey of 235 randomly selected CGCC students, 170 of them have taken an online...
In a survey of 235 randomly selected CGCC students, 170 of them have taken an online class. a. Construct, by hand, a 90% confidence interval for the proportion of all CGCC students that have taken an online class. b. Interpret your confidence interval in context of the data.
Community college students survey students at their college and ask, "Have you met with a counselor...
Community college students survey students at their college and ask, "Have you met with a counselor to develop an educational plan?" Of the 25 randomly selected students, 17 have met with a counselor to develop an educational plan. What is the 90% confidence interval for the proportion of all students at the college that have met with a counselor to develop an educational plan? (Answers may vary slightly due to rounding. Round SE to 2 decimal places before calcluating the...
The frame for an education survey includes 2000 high schools, each of which contain 1000 students....
The frame for an education survey includes 2000 high schools, each of which contain 1000 students. A sample of n=3000 students is selected in two stages. At the first stage, 100 school are randomly selected. In the second stage, 30 students are randomly selected at each school. Of the selected students, 60% reported having access to a computer at home. A published estimate gives the standard error of this percentage as 1.4%. Ignoring the finite population correction and approximating (n-1)...
1. a survey of 2000 randomly selected musician found that 304 of them are left-handed. The...
1. a survey of 2000 randomly selected musician found that 304 of them are left-handed. The 92% confidence interval for the true proportion of all musicians that are left-handed is (0.139, 0.165). What is the best conclusion to draw from this interval? There is a 90% chance that between 13.9% and 16.5% of any sample of musicians will be left-handed We can be 90% confident that the constructed confidence interval captures the unknown population proportion of musicians that are left-handed...
You take a survey of 100 students and find that 78 of them prefer chocolate over...
You take a survey of 100 students and find that 78 of them prefer chocolate over vanilla. You find a 90% confidence interval to be (0.712, .848), and you state that you are 90% confident that the proportion of students who prefer chocolate over vanilla is between .712 and .848. What do you meant when you say 90% confident? check those that apply. 1).If you were to repeatedly take random samples and calculate 90% confidence intervals, 90% of the intervals...
Answer the following: A nurse in a large university (N = 30, 000) is concerned about...
Answer the following: A nurse in a large university (N = 30, 000) is concerned about students' eye health. She takes a random sample of 75 students who don't wear glasses and finds 27 that need glasses. A) Using your graphing calculator, find a 95% confidence interval for the proportion of students who need to wear glasses but don't. (Show all work, functions, and inputs on your calculator too) B) The nurse wants to be able to estimate, with a...
A group of statistics students conducted a survey about smoking habits on campus to determine the...
A group of statistics students conducted a survey about smoking habits on campus to determine the proportion of students who believe that vaping is less harmful than smoking cigarettes. Of the 100 students surveyed, 75% think that smoking hookah is less harmful than smoking cigarettes. Since we don’t have an estimate for the population proportion (p), we will use when calculating the standard perror.a.Verify that the conditions are met to use a Normal Model. 4b. Create a 90% Confidence Interval....
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT