Question

Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient's total calcium tests gave the following readings (in mg/dl). Assume that the population of x values has an approximately normal distribution.

9.5

9.6

10.9

8.5

9.4

9.8

10.0

9.9

11.2

12.1

(a) Use a calculator with mean and sample standard deviation keys to find the sample mean reading x and the sample standard deviation s. (Round your answers to two decimal places.)

x =	mg/dl
s =	mg/dl

(b) Find a 99.9% confidence interval for the population mean of total calcium in this patient's blood. (Round your answer to two decimal places.)

lower limit	mg/dl
upper limit	mg/dl

(c) Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.

Yes. This confidence interval suggests that the patient may still have a calcium deficiency.Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.    No. This confidence interval suggests that the patient may still have a calcium deficiency.No. This confidence interval suggests that the patient no longer has a calcium deficiency

Answer 1

Given that the sample as

9.5

9.6

10.9

8.5

9.4

9.8

10.0

9.9

11.2

12.1

Hence mean can be calculated as

a) Hence mean = 10.08

Again for sample standard deviation

Hence Standard calculated as

S.d = 1.04

b) Hence a 99.9% confidence interval as

E= margin of error

Hence Error calculated as 1.5651, since t= 4.78 at 9 degree of reedom.

so, confidence interval as

    8.54= lower limit

upper limit =11.66

c) Conclusion,

No, this confidence interval suggest that the patient no longer has a calcium deficiency.

Because Since the The condition assosiated wth calcium is tat below 6 is the low calcium level or calcium deficiency.

and the lower bound is 8.54 which is higher than 6 hence there is no valcium deficency.