Question

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 400 adult residents sampled, 156 had
kids. Based on this, construct a 95% confidence interval for the
proportion ππ of adult residents who are parents in this
county.

Give your answers as decimals, to three places

Answer #1

Solution :

Point estimate () = x / n = 156 / 400 = 0.39

1 - = 0.61

Z/2 = 1.96

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.96 * ((0.39 * 0.61) / 400)

= 0.048

A 95% confidence interval for population proportion is ,

- E < < + E

0.39 - 0.048 < < 0.39 + 0.048

**0.342 <
< 0.438**

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 200 adult residents sampled, 150 had
kids. Based on this, construct a 99% confidence interval for the
proportion ππ of adult residents who are parents in this
county.
Give your answers as decimals, to three places.
< π <

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 400 adult residents sampled, 128 had
kids. Based on this, construct a 99% confidence interval for the
proportion p of adult residents who are parents in this
county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places.
____ < p < ____ Express the same answer using the point
estimate and margin of error. Give your answers as...

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 100 adult residents sampled, 40 had
kids. Based on this, construct a 95% confidence interval for the
proportion p of adult residents who are parents in this
county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places.
< p < Express the same answer using the point
estimate and margin of error. Give your answers as decimals, to
three...

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 500 adult residents sampled, 360 had
kids. Based on this, construct a 90% confidence interval for the
proportion p of adult residents who are parents in this county.
Give your answers as decimals, to 4 places. Answer = ± (Note this
is NOT in interval form, so check your answer carefull

We
wish to estimate what percent of adult residents in a certain
county are parents. Out of 500 adult residents sampled, 400 had
kids. Based on this , construct a 90% confidence interval for the
proportion of sdult residents who are parents in this
country.

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 500 adult residents sampled, 235 had
kids. Based on this, construct a 99% confidence interval for the
proportion p of adult residents who are parents in this county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places. < p < Express the same answer
using the point estimate and margin of error. Give your answers as
decimals, to...

We wish to estimate what percent of adult residents in a certain
county are parents. Out of 600 adult residents sampled, 270 had
kids. Based on this, construct a 90% confidence interval for the
proportion p p of adult residents who are parents in this
county.

1. We wish to estimate what percent of adult residents in a
certain county are parents. Out of 400 adult residents sampled, 296
had kids. Based on this, construct a 95% confidence interval for
the proportion p of adult residents who are parents in this county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places.
__< p <__ Express the same answer using the point estimate
and margin of error. Give your answers as decimals,...

QUESTION PART A: Assume that a sample is used to estimate a
population proportion p. Find the margin of error
M.E.that corresponds to a sample of size 300 with 44%
successes at a confidence level of 99.9%.
M.E. = %
Answer should be obtained without any preliminary rounding.
However, the critical value may be rounded to 3 decimal places.
Round final answer to one decimal place
QUESTION PART B: We wish to estimate what percent of adult
residents in a...

1. A poll of 2234 U.S. adults found that 31% regularly used
Facebook as a news source.
Find the margin of error and confidence interval for the
percentage of U.S. adults who regularly use Facebook as a news
source, at the 90% level of confidence. Round
all answers to 2 decimal places.
Margin of Error (as a percentage):
Confidence Interval: % to %
Find the margin of error and confidence interval for the
percentage of U.S. adults who regularly use...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 13 minutes ago

asked 17 minutes ago

asked 22 minutes ago

asked 32 minutes ago

asked 54 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago