Question

a. Compute the 95% and 99% confidence intervals on the mean based on a sample mean...

a. Compute the 95% and 99% confidence intervals on the mean based on a sample mean of 50 and population standard deviation of 10, for a sample of size 15.

b. What percent of the 95% confidence intervals would you expect to contain µ? What percent of the 95% confidence intervals would you expect to contain x̅? What percent of the 95% confidence intervals would you expect to contain 50?

c. Do you think that the intervals containing µ will differ in length from those that do? If so, why?

d. If you already knew that the population mean was 50, what value would there be in computing a confidence interval?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. Develop 90 %, 95 %, and 99% confidence intervals for population mean (µ) when sample...
1. Develop 90 %, 95 %, and 99% confidence intervals for population mean (µ) when sample mean is 10 with the sample size of 100. Population standard deviation is known to be 5. 2. Suppose that sample size changes to 144 and 225. Develop three confidence intervals again. What happens to the margin of error when sample size increases? 3. A simple random sample of 400 individuals provides 100 yes responses. Compute the 90%, 95%, and 99% confidence interval for...
Which of the following statements about confidence intervals are true? I. A 95% confidence interval will...
Which of the following statements about confidence intervals are true? I. A 95% confidence interval will contain the true μ 95% of the time. II. If P(|X̅ − μ| > 3) = 0.035. Then a value of μ that is 3 or less units away from X̅ will be included in the 99% confidence interval. III. The point estimate X̅ will be included in a 99% confidence interval.
The distribution of heights of 18-year-old men in the United States is approximately normal, with mean...
The distribution of heights of 18-year-old men in the United States is approximately normal, with mean 68 inches and standard deviation 3 inches (U.S. Census Bureau). In Minitab, we can simulate the drawing of random samples of size 20 from this population (⇒ Calc ⇒ Random Data ⇒ Normal, with 20 rows from a distribution with mean 68 and standard deviation 3). Then we can have Minitab compute a 95% confidence interval and draw a boxplot of the data (⇒...
Calculate the 99%, 95%, and 90% confidence intervals for the following information. Identify how these confidence...
Calculate the 99%, 95%, and 90% confidence intervals for the following information. Identify how these confidence intervals are similar and how they are different. Explain why. (70 points) µ = 89 σ = 9 n = 121 The 99% Confidence Interval: The 95% Confidence Interval: The 90% Confidence Interval: Similarities: Differences: Why?
Based on the confidence level used for your confidence intervals, about how many of the 10,000...
Based on the confidence level used for your confidence intervals, about how many of the 10,000 confidence intervals would you expect to contain the population mean? Explain. How many of your 10,000 confidence intervals actually did contain the population mean? Did your 250th confidence interval contain the population mean? Explain.
A researcher computed 90%, 95%, 98% and 99% confidence intervals for a population mean. However, he...
A researcher computed 90%, 95%, 98% and 99% confidence intervals for a population mean. However, he forgot to record which interval was which, and he cannot find the sample data to allow him to recreate the intervals from scratch. He now needs only the 99% confidence interval. Which one is it?        a-(37.9, 42.1)         b-(38.4, 41.6)         c-(38.1, 41.9)         d-(38.7, 41.3)
a. How well do the 95% confidence intervals do at capturing the true population mean when...
a. How well do the 95% confidence intervals do at capturing the true population mean when samples sizes are small? b. Does a larger sample size mean that the intervals are more likely to capture the true population value? Why? Note THIS is an important concept and relates back to the Sampling Distribution of Sample Means.
Question 1. Which of the following is the CORRECT interpretation of a 95% confidence interval? a)...
Question 1. Which of the following is the CORRECT interpretation of a 95% confidence interval? a) There is a 95% probability that the interval contains the population value b) There is a 95% chance that the true population value is inside the interval c) if we sampled from a population repeatedly and created confidence intervals, 95% of those confidence intervals would contain the population mean d) We are 95% sure of the sample statistic Question 2. What is the mean...
μ : Mean of variable sample size 94 99% confidence interval results: Variable Sample Mean Std....
μ : Mean of variable sample size 94 99% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit original 3.0989362 0.017739741 93 3.0522854 3.1455869 From your data, what is the point estimate, p̂ of the population proportion? Write down the confidence interval that you obtained. Interpret the result. What is the margin of error? Using the same data, construct a 98% confidence interval for the population proportion. Then, answer the following three questions: (i) What happens...
You are interested in finding a 95% confidence interval for the mean number of visits for...
You are interested in finding a 95% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 10 randomly selected physical therapy patients. 17 24 24 19 7 25 9 9 11 15 a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean number of visits per physical therapy patient is answer ___ between and answer ____ visits. c. If many groups of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT