Question: The probability that a standard normal variable, Z, is below 1.96 is 0.4750. (T/F)
Question-After an extensive advertising campaign, the manager of a company wants to estimate the proportion of potential customers that recognize a new product. She samples 120 potential consumers and finds that 54 recognize this product. She uses this sample information to obtain a 95 percent confidence interval that goes from 0.36 to 0.54.
True or False: 95 percent of the people will recognize the product between 36% and 54% of the time.
Question: A
university dean is interested in determining the proportion of
students who receive some sort of financial aid. Rather than
examine the records for all students, the dean randomly selects 200
students and finds that 118 of them are receiving financial aid.
The 95% confidence interval for p is 0.59 ± 0.07.
Interpret this interval. |
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(1) False
The probability that a standard normal variable, Z, is below 1.96 is 0.4750.
Reason:
Using Standard normal Z-table,
The probability that a standard normal variable, Z, is below 1.96 is 0.9750.
(2) True:
Reason:
Confidence interval means we are 95% confident that the true value of the population lies between these intervals thus, Statement is right.
95 per cent of the people will recognize the product between 36% and 54% of the time.
(3)
Option (A) is correct.
Reason:
Confidence interval means we are 95% confident that the true value of the population lies between these intervals thus, Statement is right.
(4)
Standard error =
=
=0.12
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