Question

The percent distribution of live​ multiple-delivery births​ (three or more​ babies) in a particular year for women 15 to 54 years old is shown in the pie chart. Find each probability. A pie chart labeled "Number of Multiple Births" is divided into seven sectors with labels and approximate sizes as a percentage of a circle as follows: 15-19, 1.3 percent; 20-24, 6.3 percent; 25-29, 21.3 percent; 30-34, 37.3 percent; 35-39, 24.6 percent; 40-44, 5.1 percent; 45-54, 4.1 percent. Number of Multiple Births 15-19 1.3% 20-24 6.3% 25-29 21.3% 30-34 37.3% 35-39 24.6% 40-44 5.1% 45-54 4.1% a. Randomly selecting a mother​ 30-39 years old ​P(30 to ​39)almost equals 0.619 ​(Round to the nearest thousandth as​ needed.) b. Randomly selecting a mother not​ 30-39 years old ​P(not 30 to ​39)almost equals 0.381 0.381 ​(Round to the nearest thousandth as​ needed.) c. Randomly selecting a mother less than 45 years old ​P(less than ​45)almost equals nothing ​(Round to the nearest thousandth as​ needed.) Enter your answer in the answer box and then click Check Answer.

Answer 1

(a)

The probability that a randomly selecting a mother​ 30-39 years old ​P(30 to ​39) is

P(30 to 39) = P(30-34) + P(35-39) = 37.3 + 24.6 = 61.9

Answer: 0.619 or 61.9%

(b)

By the complement rule, the probability that a randomly selecting a mother not​ 30-39 years old is

P(not 30-39) = 1 - P(30 tp 39) = 1 - 0.619 = 0.381

Answer: 0.381 or 38.1%

(c)

The probability that a randomly selecting a mother​ less than 45 years old ​is

P(less than 45 years) =1 - P(45-54) =1 - 0.041 = 0.959

Answer: 0.959 or 95.9%