The total cholesterol values for a certain population are approximately normally distributed with a mean of mg/100ml and a standard deviation of 20mg/100ml.
Find thetotalcholesterol valuescorresponding to the first quartile,thesecond quartileand the third quartilefor thispopulation.
Solution :
mean = = 100
standard deviation = = 20
Using standard normal table,
(a)
P(Z < z) = 0.25
P(Z < -0.67) = 0.25
z = -0.67
Using z-score formula,
x = z * +
x = -0.67 * 20 + 100 = 86.6
First quartile = 86.6
Second quartile = mean = 100
Because the normal distribution is symmetric .
P(Z < z) = 0.75
P(Z < 0.67) = 0.25
z = 0.67
Using z-score formula,
x = z * +
x = 0.67 * 20 + 100 = 113.4
Third quartile = 113.4
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