It is calculated that, in order to estimate the true mean amount of money spent by all customers at a grocery store to within $3 with 90% confidence, we require a sample of 180 customers. What sample size would be required to estimate the true mean to within $1 with 90% confidence? Your Answer:
At 90% confidence interval the critical value is z0.05 = 1.645
Margin of error = 3
or, z0.05 * = 3
or, 1.645 * = 3
or, = (3 * )/1.645
or, = 24.4676
Margin of error = 1
or, z0.05 * = 1
or, 1.645 * 24.4676/ = 1
or, n = (1.645 * 24.4676)^2
or, n = 1620
Get Answers For Free
Most questions answered within 1 hours.