Question

The following table contains observed frequencies for a sample of .

	Column Variable
Row Variable	A	B	C
P	30	58	60
Q	20	12	20

Test for independence of the row and column variables using  .

Compute the value of the  test statistic (to 2 decimals).

The -value is - Select your answer -less than .005between .005 and .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 2

What is your conclusion?

- Select your answer -Cannot reject the assumption that rows and columns are independentConclude the row variable and column variable are not independent

The following table contains observed frequencies for a sample of .

	Column Variable
Row Variable	A	B	C
P	30	58	60
Q	20	12	20

Test for independence of the row and column variables using  .

Compute the value of the  test statistic (to 2 decimals).

The -value is - Select your answer -less than .005between .005 and .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 2

What is your conclusion?

- Select your answer -Cannot reject the assumption that rows and columns are independentConclude the row variable and column variable are not independent

Answer 1

Ans:

Assume alph=0.05

Observed(fo)
Row Variable	A	B	C	Total
P	30	58	60	148
Q	20	12	20	52
Total	50	70	80	200
Expected(fe)
Row Variable	A	B	C	Total
P	37.00	51.80	59.20	148
Q	13.00	18.20	20.80	52
Total	50	70	80	200
Chi square=(fo-fe)^2/fe
Row Variable	A	B	C	Total
P	1.32	0.74	0.01	2.08
Q	3.77	2.11	0.03	5.91
Total	5.09	2.85	0.04	7.99

Test statistic:

Chi square=7.99

df=(2-1)*(3-1)=2

p-value=CHIDIST(7.99,2)=0.0184

between .01 and .025

As,p-value<0.05, reject the null hypothesis.

We reject the assumption that rows and columns are independent.